The Specificities of the General Plain Sesqualgebra

Introduction

The general plain sesqualgebra is the operation $\tilde Q\star\tilde Q_2=\tilde Q\tilde Q_2^{*}$ on the biquaternion space, the general plain sesquilinear product read as a multiplication (Introduction to the General Plain Sesqualgebra). As an element-theoretic object the block is poor: it has a right unit and no left one, no invertible element in the strict sense, no root of $-1$ and no root of $0$, and its only idempotents are the Hermitian ones. As an operator-theoretic object it is the opposite, and in a way that no other structure of the twelve reproduces. This article isolates that way and states it as a criterion of the block.

The criterion is a composition law of the right multiplications, and it is an identity about the product itself:

$$ \text{(C)}\qquad R^{\star}_{\tilde Q}R^{\star}_{\tilde Q_2}=R^{\star}_{\tilde Q\tilde Q_2}\qquad\text{for all }\tilde Q,\tilde Q_2, $$

where $R^{\star}_{\tilde Q}(\tilde Q_1)=\tilde Q_1\star\tilde Q$ and the index $\tilde Q\tilde Q_2$ on the right is the plain product of the two parameters. The block satisfies C in the forward order, and it is the only structure of the twelve that does on the right. The plain product satisfies the reversed law, $R_{\tilde Q}R_{\tilde Q_2}=R_{\tilde Q_2\tilde Q}$, so its right multiplications give the opposite monoid, and its left multiplications give the monoid, in the forward order; the general quaternionic product carries its one-sided law on the left, in the reversed order, so it too gives the opposite monoid (The Specificities of the General Quaternionic Algebra); and the remaining nine structures satisfy no one-sided composition law at all. In the whole of the twelve there are therefore exactly three structures with a one-sided law, each on one side and in one order: the plain product, the general quaternionic product and the block. The block is the unique one in which the law is on the right and in the forward order, and it holds because its right multiplications are the plain right multiplications at the conjugated index, an isotopy of the plain algebra. Everything peculiar to the block on the operator side follows from this one identity: the projector family is indexed by the plain idempotents, the right ideals coincide with the plain right ideals, and the left multiplications, being conjugate-linear, have no projector but the zero operator.

$$ L^{\star}_{\tilde Q}(\tilde Q_1)=\tilde Q\star\tilde Q_1,\qquad R^{\star}_{\tilde Q}(\tilde Q_1)=\tilde Q_1\star\tilde Q , $$

the superscript $\star$ distinguishing them from the plain operators $L_{\tilde Q}(\tilde Q_1)=\tilde Q\tilde Q_1$ and $R_{\tilde Q}(\tilde Q_1)=\tilde Q_1\tilde Q$ of One-Sided Operators on the General Plain Sesqualgebra. The subscript is the element and never the operator, so $R^{\star}_{\tilde Q}R^{\star}_{\tilde Q_2}$ is the composite. An element of the twelve is written $\circ$; a projector is an idempotent operator, and the zero operator is one.

The Isotope Identity

Theorem (the dictionary). For every $\tilde Q$,

$$ \boxed{\;R^{\star}_{\tilde Q}=R_{\tilde Q^{*}},\qquad L^{\star}_{\tilde Q}=L_{\tilde Q}\,\eta,\qquad R^{\star}_{\tilde Q}=\eta\,L^{\star}_{\tilde Q},\qquad L^{\star}_{\tilde Q}=\eta\,R^{\star}_{\tilde Q}\;}. $$

The right multiplication of the block is the plain right multiplication at the conjugated index; the left multiplication of the block is the plain left multiplication composed with the involution, hence conjugate-linear; and the involution $\eta$ carries each one-sided family to the other, $R^{\star}_{\tilde Q}=\eta\circ L^{\star}_{\tilde Q}$ and $L^{\star}_{\tilde Q}=\eta\circ R^{\star}_{\tilde Q}$.

Proof. The first identity is $R^{\star}_{\tilde Q}(\tilde Q_1)=\tilde Q_1\star\tilde Q=\tilde Q_1\tilde Q^{*}=R_{\tilde Q^{*}}(\tilde Q_1)$. The second is $L^{\star}_{\tilde Q}(\tilde Q_1)=\tilde Q\star\tilde Q_1=\tilde Q\tilde Q_1^{*}=L_{\tilde Q}(\eta(\tilde Q_1))$. For the third, $\eta\bigl(L^{\star}_{\tilde Q}(\tilde Q_1)\bigr)=\eta(\tilde Q\tilde Q_1^{*})=\bigl(\tilde Q\tilde Q_1^{*}\bigr)^{*}=\tilde Q_1\tilde Q^{*}=R^{\star}_{\tilde Q}(\tilde Q_1)$, using that ${}^{*}$ is an involution; the fourth is the same relation with the two sides exchanged.

Corollary (linearity, faithfulness, the unit). The right multiplications $R^{\star}_{\tilde Q}$ are $\mathbb{C}$-linear and faithful in $\tilde Q$; the left multiplications $L^{\star}_{\tilde Q}$ are conjugate-linear and faithful; $R^{\star}_{e_t}=\mathrm{id}$ is the right unit and $L^{\star}_{e_t}=\eta$ is the involution.

Proof. The plain $R$ and $L$ are $\mathbb{C}$-linear and $\eta$ is conjugate-linear; faithfulness is that of the plain operators, since $\eta$ and ${}^{*}$ are bijections. The unit statements are $\tilde Q_1\star e_t=\tilde Q_1 e_t^{*}=\tilde Q_1$ and $e_t\star\tilde Q_1=e_t\tilde Q_1^{*}=\tilde Q_1^{*}$.

Remark (the price of the dictionary). In the matrix model $\mathsf{M}_2$ the identities read $\mathsf{M}_2(R^{\star}_{\tilde Q}\tilde Q_1)=\mathsf{M}_2(\tilde Q_1)\mathsf{M}_2(\tilde Q)^{\dagger}$ and $\mathsf{M}_2(L^{\star}_{\tilde Q}\tilde Q_1)=\mathsf{M}_2(\tilde Q)\mathsf{M}_2(\tilde Q_1)^{\dagger}$: the right multiplication is right multiplication by the conjugate transpose, and the left multiplication is left multiplication by it. Every statement below is an element statement about the plain algebra with a conjugated index, and the operator is linear on the right and conjugate-linear on the left. The asymmetry between the two sides is the content of the corollary on the projectors.

The Criterion

Definition (the right-composition law). The right multiplications of a product $\circ$ on $\mathbb{B}$ are the operators $R^{\circ}_{\tilde Q}(\tilde Q_1)=\tilde Q_1\circ\tilde Q$. They satisfy the right-composition law when they compose in the forward order and are indexed by the plain product of the two parameters, juxtaposition being the plain product,

$$ R^{\circ}_{\tilde Q}R^{\circ}_{\tilde Q_2}=R^{\circ}_{\tilde Q\tilde Q_2}\qquad\text{for all }\tilde Q,\tilde Q_2, $$

and they satisfy the reversed law when $R^{\circ}_{\tilde Q}R^{\circ}_{\tilde Q_2}=R^{\circ}_{\tilde Q_2\tilde Q}$.

Theorem (the criterion). The block satisfies the right-composition law, with the index read in the plain product of the two parameters:

$$ \boxed{\;R^{\star}_{\tilde Q}R^{\star}_{\tilde Q_2}=R^{\star}_{\tilde Q\tilde Q_2}\qquad\text{for all }\tilde Q,\tilde Q_2\;}. $$

Proof. By the dictionary $R^{\star}_{\tilde Q}R^{\star}_{\tilde Q_2}=R_{\tilde Q^{*}}R_{\tilde Q_2^{*}}=R_{\tilde Q_2^{*}\tilde Q^{*}}$, the plain composition law being the reversed one. And $\tilde Q_2^{*}\tilde Q^{*}=(\tilde Q\tilde Q_2)^{*}$, because ${}^{*}$ is an anti-automorphism; so the composite is $R_{(\tilde Q\tilde Q_2)^{*}}=R^{\star}_{\tilde Q\tilde Q_2}$, which is the display.

Corollary (the right multiplications form a monoid). The family $\{R^{\star}_{\tilde Q}:\tilde Q\in\mathbb{B}\}$ is stable under composition, and the assignment $\tilde Q\mapsto R^{\star}_{\tilde Q}$ is a monoid isomorphism from the multiplicative monoid $(\mathbb{B},\cdot)$ onto it, in the forward order. Consequently the block's right multiplications are a copy of the plain multiplicative monoid, and not of its opposite.

Proof. The law gives closure and the multiplicativity of the assignment; it is injective by the faithfulness of the dictionary, and it is onto its image by construction. The forward order is the law itself, as opposed to the plain law $R_{\tilde Q}R_{\tilde Q_2}=R_{\tilde Q_2\tilde Q}$.

Remark (why the block and no other). Exactly three of the twelve structures carry a one-sided composition law, and the table of §The Isolation among the Twelve records which. The plain product carries it on both sides, forward on the left and reversed on the right; the general quaternionic product carries it on the left and reversed; the block carries it on the right and forward. The block is the structure in which the forward order is carried by the right multiplications, and this is exactly the statement that the twist sits in the second slot and is an anti-automorphism: the conjugation in $\tilde Q\tilde Q_2^{*}$ reverses the order of the plain product, and the reversal, read on the right multiplications, undoes the reversal of the composition. In the nine remaining structures neither side closes, and the reason is the same in every case: a derived part mixes the two slots, and the two products that are not the plain one conjugate a slot, which turns a one-sided multiplication into an operator carrying two independent parameters. The left multiplications of the block do not form a monoid, because the twist is in the slot a left multiplication reads: $L^{\star}_{\tilde Q}L^{\star}_{\tilde Q_2}=L_{\tilde Q}\eta L_{\tilde Q_2}\eta=L_{\tilde Q}R_{\tilde Q_2^{*}}$, a mixed operator of the two independent parameters $\tilde Q,\tilde Q_2$, which is a two-sided operator only in the diagonal case $\tilde Q_2=\lambda\tilde Q^{*}$ (Mixed Inner Conjugation on the General Plain Sesqualgebra), and is not the left multiplication of the block at any single element in general.

The Isolation among the Twelve

Theorem (the specificity). Of the twelve structures of The Algebraic Structures over the Biquaternion $\mathbb{C}$ Space, the general plain sesqualgebra is the only one whose right multiplications satisfy the right-composition law in the forward order.

Proof. The block satisfies it by §The Criterion. The other eleven are the three remaining general products together with the eight parts got by symmetrising or antisymmetrising the four. The three general products are disposed of by the table below: $\tilde Q\tilde Q_2$ carries the forward law on the left and the reversed law on the right, $\tilde Q^{\natural}\tilde Q_2$ carries the reversed law on the left, $\tilde Q\tilde Q_2^{*}$ is the block, and $\tilde Q^{\natural}\tilde Q_2^{*}$ conjugates both slots and closes on neither side. Each of the eight derived parts mixes the two slots in its multiplication, $R^{\circ}_{\tilde Q}(\tilde Q_1)=\tfrac12(\tilde Q_1\circ\tilde Q\pm\tilde Q\circ\tilde Q_1)$, so the composite of two of them is a sum of four products and is not a single multiplication at any element in general.

family members right law left law
general GPA, GQA, GPS, GQS reversed, none, forward, none forward, reversed, none, none
symmetric SPA, SQA, SPS, SQS none none
antisymmetric APA, AQA, APS, AQS none none

Only three of the twelve carry a one-sided law, each on one side: the plain product (forward on the left, reversed on the right), the general quaternionic product (reversed, on the left) and the block (forward, on the right). The block is the unique one whose law is on the right and in the forward order, and the reason is that its twist sits in the second slot alone and is an anti-automorphism: the conjugation reverses the order of the plain product, and that reversal, read on the right multiplications, undoes the reversal of the plain composition. In the nine others neither side closes, because a derived part mixes the two slots or because a product conjugates a slot. The left multiplications of the block close nowhere either, because the twist is in the slot a left multiplication reads: $L^{\star}_{\tilde Q}L^{\star}_{\tilde Q_2}=L_{\tilde Q}\eta L_{\tilde Q_2}\eta=L_{\tilde Q}R_{\tilde Q_2^{*}}$, a mixed operator of the two independent parameters $\tilde Q,\tilde Q_2$, a two-sided operator only in the diagonal case $\tilde Q_2=\lambda\tilde Q^{*}$ (Mixed Inner Conjugation on the General Plain Sesqualgebra).

The Projectors

Theorem (the projector criterion). The operator $R^{\star}_{\tilde Q}$ is a projector if and only if $\tilde Q$ is an idempotent of the plain product, and the operator $L^{\star}_{\tilde Q}$ is a projector if and only if $\tilde Q=0$.

Proof. By the composition law $R^{\star}_{\tilde Q}{}^{2}=R^{\star}_{\tilde Q\tilde Q}$, and by faithfulness the equality $R^{\star}_{\tilde Q}{}^{2}=R^{\star}_{\tilde Q}$ is $\tilde Q\tilde Q=\tilde Q$. For the left side, $L^{\star}_{\tilde Q}$ is conjugate-linear, and its composite with itself is $\mathbb{C}$-linear; a conjugate-linear operator equal to a $\mathbb{C}$-linear one is zero, so $L^{\star}_{\tilde Q}{}^{2}=L^{\star}_{\tilde Q}$ forces $L^{\star}_{\tilde Q}=0$, that is $\tilde Q=0$ by faithfulness.

Corollary (the family of projectors, and the disowning). The elements whose right multiplication is a projector are the plain idempotents: $0$, $e_t$ and the family $\tfrac12(e_t+\vec\Xi)$ over the pure roots $\vec\Xi$ of $+1$, of complex dimension two. The idempotents of the block itself are only the Hermitian ones, $0$, $e_t$ and the $\tfrac12(e_t+\vec\Xi)$ over the real unit vectors $\vec u$, a family of real dimension two.

Proof. By the criterion and by Idempotents of the General Plain Algebra, whose idempotents are $0$, $e_t$ and the $\tfrac12(e_t+\vec\Xi)$ with $\vec\Xi^{2}=e_t$. The idempotents of the block are computed in Square Roots of One and the Idempotents of the General Plain Sesqualgebra: they are the Hermitian idempotents of the algebra, $0$, $e_t$ and the $\tfrac12(e_t+\vec\Xi)$.

Remark (the mirror of the general quaternionic case). The block has a full complex two-dimensional family of projectors and recognizes as its own idempotents only the real two-dimensional Hermitian subfamily; the general quaternionic product has the same full family of projectors on the left and the same two idempotents. The two articles are the two sides of one phenomenon, the isotope with a conjugated index: the projectors come from the plain idempotents, and the idempotents of the structure are the elements whose own square is themselves, which the conjugation generally destroys. The count of the projectors is that of One-Sided Operators on the General Plain Sesqualgebra, read through the dictionary.

The One-Sided Ideals

Theorem (the right ideals coincide and the left ones do not). Let $I$ be a subspace of $\mathbb{B}$. Then

$$ \boxed{\;I\ \text{is a right ideal of }\star\iff I\ \text{is a right ideal of the plain product}\;}, $$

and

$$ I\ \text{is a left ideal of }\star\iff I\ \text{is a left ideal of the plain product and }I^{*}=I . $$

Proof. $I$ is a right ideal of $\star$ when $I\star\mathbb{B}\subseteq I$, and $I\star\tilde Q=I\tilde Q^{*}$, so $I\star\mathbb{B}=I\mathbb{B}$ because $\tilde Q\mapsto\tilde Q^{*}$ is a bijection; hence the first equivalence. For the second, $I$ is a left ideal of $\star$ when $\mathbb{B}\star I\subseteq I$, that is $\mathbb{B}I^{*}\subseteq I$. Taking the parameter $e_t$, whose left action is the involution, gives $I^{*}\subseteq I$, and the two spaces have the same dimension, so $I^{*}=I$; with that, $\mathbb{B}I^{*}=\mathbb{B}I\subseteq I$ is exactly the plain left-ideal condition, and the converse is immediate.

Corollary (the asymmetry). The right ideals of the block are exactly those of the plain product, with no further condition, and they are as many as in the matrix algebra: the minimal ones are the $\tilde\Pi\mathbb{B}$ over the primitive plain idempotents. The left ideals are only the two trivial ones, $0$ and $\mathbb{B}$, and the block has no proper nonzero left ideal.

Proof. The two displays are the theorem, and a subspace stable under the involution is not a further condition but a strong one. For the sharpening, let $I$ be a left ideal of $\star$, so $I^{*}=I$ and $\mathbb{B}I\subseteq I$. For $x\in I$ and $y\in\mathbb{B}$ the element $y^{*}x^{*}$ lies in $\mathbb{B}I\subseteq I$, hence $xy=(y^{*}x^{*})^{*}$ lies in $I^{*}=I$; therefore $I\mathbb{B}\subseteq I$ and $I$ is two-sided. By the simplicity of $\mathbb{B}$ (The Biquaternion Sesqualgebra Is Simple) a two-sided ideal is $0$ or $\mathbb{B}$. The strictness on the left is witnessed by a primitive plain idempotent $\tilde\Pi$: the space $\mathbb{B}\tilde\Pi$ is a minimal left ideal of the plain product, and $(\mathbb{B}\tilde\Pi)^{*}=\tilde\Pi^{*}\mathbb{B}\neq\mathbb{B}\tilde\Pi$, so it is not stable and not a left ideal of the block, while the space $\tilde\Pi\mathbb{B}$ is a minimal right ideal of the plain product and is a right ideal of the block.

Remark (the right is the faithful side). The block is right-faithful: its right ideals, its projectors and its multiplicative monoid are the plain ones, read at the conjugated index, and the right side carries the associative theory without loss. The left side does not: it carries the involution, which is conjugate-linear, and its one-sided theory collapses to the two trivial ideals. The general quaternionic product is the mirror image, left-faithful and right-blind; the two articles are read together, and the pair is the element-level statement that the twist of the two sesquilinear products sits in the two different slots.

The Involution and the Inversion

Corollary (the involution exchanges the two families). For every $\tilde Q$,

$$ R^{\star}_{\tilde Q}=\eta\,L^{\star}_{\tilde Q},\qquad L^{\star}_{\tilde Q}=\eta\,R^{\star}_{\tilde Q},\qquad \eta\,R^{\star}_{\tilde Q}\,\eta=L_{\tilde Q},\qquad (R^{\star}_{\tilde Q})^{-1}=R^{\star}_{\tilde Q^{-1}} , $$

the last on the invertible elements, where $\tilde Q^{-1}$ is the plain inverse and the inverse is the operator inverse.

Proof. The first two are the dictionary. For the third, $\eta R^{\star}_{\tilde Q}\eta(\tilde Q_1)=\eta\bigl(\eta(\tilde Q_1)\star\tilde Q\bigr)=\eta\bigl(\tilde Q_1^{*}\tilde Q^{*}\bigr)=\bigl(\tilde Q_1^{*}\tilde Q^{*}\bigr)^{*}=\tilde Q\tilde Q_1=L_{\tilde Q}(\tilde Q_1)$. For the fourth, $R^{\star}_{\tilde Q}=R_{\tilde Q^{*}}$ is invertible exactly when $\tilde Q^{*}$ is a plain unit, that is exactly when $\tilde Q$ is, and $(R_{\tilde Q^{*}})^{-1}=R_{(\tilde Q^{*})^{-1}}=R_{(\tilde Q^{-1})^{*}}=R^{\star}_{\tilde Q^{-1}}$.

Remark (the inverse of the block at the operator level). The invertibility criterion of the block is the non-vanishing of the norm $\langle\tilde Q\rangle_{\natural}=\tilde Q\tilde Q^{\natural}$ (Norm and Invertibility in the General Plain Sesqualgebra), and the operator family carries the plain group of units $\mathbb{B}^{\times}$ faithfully; the operator inverse is indexed by the plain inverse, $(R^{\star}_{\tilde Q})^{-1}=R^{\star}_{\tilde Q^{-1}}$, and the block's own inverse, $\tilde Q^{-1\star}=(\tilde Q^{-1})^{*}$, is the star-conjugate of the plain one. The right multiplication is the side that carries the plain inverse, and the involution ${}^{*}$ moves between the two, which is the operator form of the fact that the two slots of the block are not symmetric. The involution $\tilde Q\mapsto \tilde Q^{-1\star}$ of the block is treated with the two-sided operators in Mixed Inner Conjugation on the General Plain Sesqualgebra.

The Consequence

Corollary (what belongs to the block alone). The block is the only one of the twelve whose right multiplications satisfy the forward composition law $R^{\star}_{\tilde Q}R^{\star}_{\tilde Q_2}=R^{\star}_{\tilde Q\tilde Q_2}$, and it is for this reason the only one whose right side carries the plain theory: the right projector criterion is read on the plain idempotents, the right ideals coincide with the plain right ideals, and the right multiplications are a faithful copy of the multiplicative monoid in the forward order. Its left side does not: the left multiplications are conjugate-linear, their only projector is the zero operator, and the left ideals collapse to $0$ and $\mathbb{B}$. The general quaternionic product is the mirror image on the left, in the reversed order, and the general plain product is the associative case in which the left order is forward and the right order is reversed.

Remark (the criterion and the family of the specificities). The specificities of the general plain algebra read the left-alternativity identity $L_{\tilde Q_1}^{2}=L_{\tilde Q_1\circ\tilde Q_1}$; the specificities of the general quaternionic algebra read the isotope identity $L_{\tilde Q}=L_{\tilde Q^{\natural}}$ with its projector criterion on the left; the specificities of the symmetric quaternionic algebra read the identity $L_{\tilde Q_1}^{2}=Q_{1t}L_{\tilde Q_1}$; and the specificities of the symmetric plain sesqualgebra read the two clauses conjugate-commutativity and centrality. The present article reads the right-composition law, which is the forward-order identity of the right multiplications, and it is the only one of the family stated on that side. The four criteria are independent, and each identifies the block for which it is stated against the other eleven.

Summary

The general plain sesqualgebra satisfies the right-composition law $R^{\star}_{\tilde Q}R^{\star}_{\tilde Q_2}=R^{\star}_{\tilde Q\tilde Q_2}$ in the forward order, and it is the only one of the twelve structures that does. The law is the operator form of the isotope identity $R^{\star}_{\tilde Q}=R_{\tilde Q^{*}}$, the right multiplication of the block being the plain right multiplication at the conjugated index; because the conjugation is an anti-automorphism, the reversal it introduces cancels the reversal of the plain composition law, and the right multiplications of the block form a monoid isomorphic (not anti-isomorphic) to the multiplicative monoid of the algebra. Exactly three of the twelve structures carry a one-sided law: the plain product (forward on the left, reversed on the right), the general quaternionic product (reversed, on the left), and the block (forward, on the right); the general quaternionic sesquilinear product and the eight derived parts satisfy none. The consequences are the operator face of the block: the projector criterion is that $R^{\star}_{\tilde Q}$ is a projector exactly when $\tilde Q$ is a plain idempotent, a family of complex dimension two, while the block's own idempotents are only the Hermitian ones, of real dimension two; the left multiplications are conjugate-linear with no projector but the zero operator; the right ideals of the block are exactly the plain right ideals, and the left ideals collapse to the two trivial ones, $0$ and $\mathbb{B}$, so the block is right-faithful and left-blind; and the involution exchanges the two families, $\eta R^{\star}_{\tilde Q}\eta=L_{\tilde Q}$, with $(R^{\star}_{\tilde Q})^{-1}=R^{\star}_{\tilde Q^{-1}}$ on the units. The block is the right-handed mirror of the general quaternionic product, and the pair of criteria is the element-level statement that the twist of the two sesquilinear products sits in the two different slots.

Summary of Notation

Symbol Meaning
$\tilde Q\star\tilde Q_2=\tilde Q\tilde Q_2^{*}$ the product of the block
$R^{\star}_{\tilde Q}(\tilde Q_1)=\tilde Q_1\star\tilde Q$ the right multiplication of the block
$L^{\star}_{\tilde Q}(\tilde Q_1)=\tilde Q\star\tilde Q_1$ the left multiplication of the block, conjugate-linear
$R^{\circ}_{\tilde Q}R^{\circ}_{\tilde Q_2}=R^{\circ}_{\tilde Q\tilde Q_2}$ the right-composition law, the criterion, the index in the plain product
$R^{\star}_{\tilde Q}=R_{\tilde Q^{*}}$ the isotope identity, the dictionary
$L^{\star}_{\tilde Q}=L_{\tilde Q}\eta$ the left multiplication is plain-composed-with-the-involution
$\eta\,R^{\star}_{\tilde Q}\,\eta=L_{\tilde Q}$ the involution conjugated reads the plain left multiplication
$R^{\star}_{\tilde Q}=\eta L^{\star}_{\tilde Q}$ the involution exchanges left and right
$R^{\star}_{\tilde Q}$ a projector $\iff\tilde Q$ a plain idempotent the projector criterion
$L^{\star}_{\tilde Q}$ a projector $\iff\tilde Q=0$ the collapse on the left
$I\star\mathbb{B}\subseteq I\iff I$ plain right ideal the right ideals coincide
$\mathbb{B}\star I\subseteq I\iff I$ plain left ideal with $I^{*}=I$ the left ideals are the two trivial ones, $0$ and $\mathbb{B}$
$(R^{\star}_{\tilde Q})^{-1}=R^{\star}_{\tilde Q^{-1}}$ the operator inverse, indexed by the plain inverse

Further Reading